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355309 IN5812 7C954DX 35LET SMB3EZ19 LM386L 30100 1N3294A
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    RC4200 RC4200AM RC4200N RC4200M RC4200AN

Fairchild Semiconductor
Part No. RC4200 RC4200AM RC4200N RC4200M RC4200AN
OCR Text ...ltiplier/Divider VX VY R0 R4 solving for V 0 = ------------------------------------VZ R1 R2 For a multiplier circuit V Z = V R = cons tan t R0 R4 Therefore: V 0 = V X V Y K where K = -------------------VR R1 R2 For a divider circuit V Y ...
Description From old datasheet system
Analog Multiplier

File Size 204.41K  /  23 Page

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    L6506 L6506D 1392

STMicroelectronics
意法半导
Part No. L6506 L6506D 1392
OCR Text ...ons 1 and 2 into equation 3 and solving for the value of R1 the following equations for the external components can be derived : 1 (4) R1 = ( - 2) RIN DC C1 = T1 0.69 R1 (5) Looking at equation 1 it can easily be seen that the minimum pulse...
Description    CURRENTCONTROLLER FOR STEPPING MOTORS
From old datasheet system
CURRENT CONTROLLER FOR STEPPING MOTORS

File Size 74.93K  /  8 Page

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    MUR8100EG MUR880E MUR8100E

ONSEMI[ON Semiconductor]
Part No. MUR8100EG MUR880E MUR8100E
OCR Text ...ode, and goes to zero at t2. By solving the loop equation at the point in time when S1 is opened; and calculating the energy that is transferred to the diode it can be shown that the total energy transferred is equal to the energy stored in...
Description 8A 800V Ultrafast Rectifier
8A 1000V Ultrafast Rectifier
(MUR8100E / MUR880E) SWITCHMODE Power Rectifiers

File Size 94.45K  /  6 Page

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    PSD835F1-12B81 PSD835F1-12B81I PSD835F1-12J PSD835F1-12JI PSD835F1-12M PSD835F1-12MI PSD835F1-12U PSD835F1-12UI PSD835F1

STMICROELECTRONICS[STMicroelectronics]
Part No. PSD835F1-12B81 PSD835F1-12B81I PSD835F1-12J PSD835F1-12JI PSD835F1-12M PSD835F1-12MI PSD835F1-12U PSD835F1-12UI PSD835F1-15B81 PSD835F1-15B81I PSD835F1-15J PSD835F1-15JI PSD835F1-15M PSD835F1-15MI PSD835F1-15U PSD835F1-15UI PSD835F1-20B81 PSD835F1-20B81I PSD835F1-20J PSD835F1-20JI PSD835F1-20M PSD835F1-20MI PSD835F1-20U PSD835F1-20UI PSD835F1-70B81 PSD835F1-70B81I PSD835F1-70J PSD835F1-70JI PSD835F1-70M PSD835F1-70U PSD835F1-70UI PSD835F1-90B81 PSD835F1-90B81I PSD835F1-90J PSD835F1-90JI PSD835F1-90M PSD835F1-90MI PSD835F1-90U PSD835F1-A-12B81I PSD835F1-A-12J PSD835F1-A-12JI PSD835F1-A-12M PSD835F1-A-12MI PSD835F1-A-12U PSD835F1-A-12UI PSD835F1-A-15B81 PSD835F1-A-15B81I PSD835F1-A-15J PSD835F1-A-15JI PSD835F1-A-15M PSD835F1-A-15MI PSD835F1-A-15UI PSD835F1-A-20B81 PSD835F1-A-20B81I PSD835F1-A-20J PSD835F1-A-20JI PSD835F1-A-20M PSD835F1-A-20MI PSD835F1-A-20U PSD835F1-A-20UI PSD835F1-A-70B81 PSD835F1-A-70B81I PSD835F1-A-70J PSD835F1-A-70JI PSD835F1-A-70M PSD835F1-A-70MI PSD835F1-A-70UI PSD835F1-A-90B81 PSD835F1-A-90B81I PSD835F1-A-90J PSD835F1-A-90JI PSD835F1-A-90M PSD835F1-A-90MI PSD835F1-A-90U PSD835F1-A-90UI PSD835F1-B-12B81 PSD835F1-B-12B81I PSD835F1-B-12J PSD835F1-B-12JI PSD835F1-
OCR Text ... memories is an industry first, solving key problems faced by designers and manufacturing houses, such as: * First time programming - How do I get firmware into the flash the very first time? JTAG is the answer, program the PSD while bl...
Description Configurable Memory System on a Chip for 8-Bit Microcontrollers

File Size 564.49K  /  110 Page

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    LC75366 LC75366M

SANYO[Sanyo Semicon Device]
Part No. LC75366 LC75366M
OCR Text ... + 10 * Z1 R2 + R3 + 10 * Z2 solving the above equations gives: Z1 178.3 k and Z2 = 176 No. 4929-10/11 LC75366, 75366M Therefore, under such conditions where f = 1 kHz, specifications may be satisfied if C (capacitor) having these ...
Description CMOS LSI
Two-Channel Electronic Volume Control

File Size 242.19K  /  11 Page

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    Motorola
Part No. MC68LK332
OCR Text ...s: P D = K / ( T J + 273C ) (2) solving equations 1 and 2 for K gives: K = P D x ( T A + 273C ) + JA x P D 2 (3) where K is a constant pertaining to the particular part. K can be determined from equation (3) by measuring PD (at equi...
Description Technical Supplement 16.78 MHz Electrical Characteristics

File Size 223.99K  /  28 Page

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    Dallas
Part No. DS1836D DS1836C DS1836B DS1836A DS1836
OCR Text ... Figure 3. A simple approach to solving the equation is to select a value for R2 high enough to keep power consumption low, and solve for R1. The flexibility of the IN input pin allows for detection of power loss at the earliest point in a ...
Description 3.3V/5V MicroManager

File Size 117.35K  /  9 Page

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    MUR1100E MUR190E ON2734

ON Semiconductor
MOTOROLA[Motorola Inc]
MOTOROLA[Motorola, Inc]
Part No. MUR1100E MUR190E ON2734
OCR Text ...ode, and goes to zero at t2. By solving the loop equation at the point in time when S1 is opened; and calculating the energy that is transferred to the diode it can be shown that the total energy transferred is equal to the energy stored in...
Description 1 A, 900 V, SILICON, SIGNAL DIODE
ULTRAFAST RECTIFIERS 1.0 AMPERE 900-1000 VOLTS
From old datasheet system

File Size 121.70K  /  6 Page

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